Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

Possible Duplicate:
Phase shift of 180 degrees on reflection from optically denser medium

I've read in a physics book for musicians that, when a soundwave hits a near-solid object, it generates an almost completely in-phase echo. However, when the wave hits a near-vacuum, the echo generated is almost completely out of phase echo.

Can someone explain, in detail, why this happens (or point me at a detailed explanation)?

(My math-fu is fairly strong, but my physics-fu is not).

share|improve this question

marked as duplicate by Emilio Pisanty, Manishearth Dec 13 '12 at 10:02

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add comment

1 Answer 1

up vote 3 down vote accepted

It comes down to the change in the speed of sound at the interface. The speed of sound in air is approximately 343 m/s. The speed of sound in a solid object is typically much, much higher because the stiffness is much higher. For example, copper is 3901 m/s, brick is 4176 m/s and there are many other materials you can look at for reference.

On the other hand, a near-vacuum has extremely few molecules to transmit the sound. This means sound does not travel very well through it and the speed of sound is much, much lower. Contrary to popular belief, it's not zero for all frequencies, but for many sounds they just don't travel very well without molecules to transmit them.

So we have two conditions. In the first, the wave is going from one medium to another where the speed of sound is higher (the solid object) and the second the wave is going from one medium to another where the speed of sound is lower (the near vacuum). An animation of these two effects can be seen at the bottom of this page.

You can see that the transmission to a lower wave speed results in a phase shift (the wave is weakened and inverts) while the transmission to the higher wave speed results in just an amplitude weakening. A mathematical treatment of waves crossing the boundaries is performed using Maxwell's Equations, but an electromagnetic wave and a sound wave obey the same (basic) governing equations.

The primary mechanism in both cases is that a wave impacting a surface generates a wave in the second material. That wave will leave at either a higher or lower speed than the incident wave. If the properties of both materials were identical, the wave would pass through and there would be no reflection (no echo).

share|improve this answer
1  
Could you expand on how sounds of some frequencies are supposed to travel through vacua? –  Claudius Dec 11 '12 at 18:59
    
Near-vacuum. Few parts of space are totally void of molecules to transmit sound waves. Sound waves cannot be transmitted at wavelengths less than the mean free path, which I admit is a very large wavelength in interplanetary space (~1AU). But it's not zero. And we're talking near-vacuum, which isn't as sparse as outer space. –  tpg2114 Dec 11 '12 at 19:33
    
Ah, ok. Just to throw in some numbers: $\lambda \approx 1 \textrm{ m}$ for audible sound waves (at $f = 300 \textrm{ Hz}$), the mean free path being something on the orders of tens or hundreds of metres in outer space (en.wikipedia.org/wiki/… , en.wikipedia.org/wiki/Vacuum#Measurement) –  Claudius Dec 11 '12 at 19:40
    
By no standards would you expect to hear something in outer space. And the likelihood that enough molecules are near your sound source, even if it was at the right wavelength, is very small. But this being a physics site, I figured zero isn't zero unless it's exact :) –  tpg2114 Dec 11 '12 at 19:51
add comment

Not the answer you're looking for? Browse other questions tagged or ask your own question.