Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

The problem I am working on is:

Big Ben, the Parliament tower clock in London, has an hour hand 2.70 m long with a mass of 300 kg, and a minute hand 4.20 m long with a mass of 100 kg (see figure below). Calculate the total rotational kinetic energy of the two hands about the axis of rotation. (You may model the hands as long, thin rods rotated about one end. Assume the hour and minute hands are rotating at a constant rate of one revolution per 12 hours and 60 minutes, respectively.)

(Converted) Angular Speed of Clock Hands:

Hour Hand $1.45\cdot10^{-4}~rad/s$

Minute Hand $1.75\cdot10^{-3}~rad/s$

Rotational Moment of Inertia:

Hour Hand $I=1/3(300~kg)(2.70~m)^2=729~kg\cdot m^2$

Minute Hand $I=1/3(100~kg)(4.20~m)^2=243~kg\cdot m^2$

Rotational Kinetic Energy:

$K_{rot}=1/2(729~kg\cdot m^2)(1.45\cdot10^{-4}~rad/s)^2+1/2(243~kg\cdot m^2)(1.75\cdot10^{-3}~rad/s)^2$

When I calculate this, it comes out incorrect, what has happened?

share|improve this question
1  
It looks like your angular speed of the minute hand is an order of magnitude off. The rest of it looks good. –  user16454 Dec 1 '12 at 19:56
add comment

1 Answer

up vote 2 down vote accepted

The angular speed of the minute hand is actually $1.75\times 10^{-3} rad/s$. Always do a quick consistency check on your calculations. The hour hand is moving at roughly 1/10 angular speed so the orders of magnitude should differ by ~1.

share|improve this answer
    
Even with the corrected values, I still get a wrong answer. The answer yielded from the calculations above is $3.80\cdot 10^{-4} J$, which is wrong. –  Mack Dec 2 '12 at 13:31
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.