# Is this $W_{r} = \frac{1}{2}kx^2$ procedure correct [closed]

I have a $0.40 Kg$ of mass that has $v= 0.5 m/s$, and then crashes with a spring with constant $k = 750N/m$

Whats the distance that the spring was compressed?

I was using the equation $W_{r} = \frac{1}{2}kx^2$

so

$\frac{1}{2}(0.4)(0.5*0.5) = \frac{1}{2}(750)(x^2)$

so $x = 0.011 m$

Is this correct? what is the solution?

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## closed as too localized by David Z♦Nov 28 '12 at 20:12

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Hi cMinor - generally we discourage questions that just ask for someone to check your work. Once you have identified the specific concept that you're not sure about, that's the point at which it's appropriate to ask a question here. –  David Z Nov 28 '12 at 20:12

Assuming a "resort" is a "spring" then your method is correct (conservation of energy); I get $x=0.0115 m$ as my answer.