# Is this $W_{r} = \frac{1}{2}kx^2$ procedure correct [closed]

I have a $0.40 Kg$ of mass that has $v= 0.5 m/s$, and then crashes with a spring with constant $k = 750N/m$

Whats the distance that the spring was compressed?

I was using the equation $W_{r} = \frac{1}{2}kx^2$

so

$\frac{1}{2}(0.4)(0.5*0.5) = \frac{1}{2}(750)(x^2)$

so $x = 0.011 m$

Is this correct? what is the solution?

-

## closed as too localized by David Z♦Nov 28 '12 at 20:12

This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

Hi cMinor - generally we discourage questions that just ask for someone to check your work. Once you have identified the specific concept that you're not sure about, that's the point at which it's appropriate to ask a question here. – David Z Nov 28 '12 at 20:12

EDIT: Corrected by using a real calculator instead of my brain:

Assuming a "resort" is a "spring" then your method is correct (conservation of energy); I get $x=0.0115 m$ as my answer.

-
Could you please write down your computations? I do not know where I am wrong – cMinor Nov 28 '12 at 19:16
i.e. you are correct, I just can't take square roots with my head very well :-P – levitopher Nov 28 '12 at 19:24