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Or does it exist mathematically? Is it really inconsistent with a common-sense, mathematics or known physical laws?

As far as I understand, if it exists, it must be far away from the "positive" matter because of repelling force, so it explains why there is no observations of such matter.

It would be also very consistent with the idea that the total energy of the Universe is zero. Doesn't it imply that the total mass of the Universe is zero?

Can you please clarify the statements below that seem to contradict each other?

1) "all structures that exist mathematically exist also physically" -Max Tegmark.

2) Despite being completely inconsistent with a common-sense approach and the expected behavior of "normal" matter, negative mass is completely mathematically consistent and introduces no violation of conservation of momentum or energy.

3) Such matter would violate one or more energy conditions and show some strange properties, stemming from the ambiguity as to whether attraction should refer to force or the oppositely oriented acceleration for negative mass.

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Serg: as Qmechanic corrected you, "matter" is the actual stuff, not a number, so it can't be positive or negative. The thing that has a numerical value is "mass", not "matter". Now, there is no "negative matter" and no matter has "negative mass". In particular, antiparticles and antimatter are sort of opposite to the "normal" particles when it comes to electric and other charges, but they still have a positive mass and attractive gravity etc., see e.g. motls.blogspot.cz/2010/09/… –  Luboš Motl Nov 23 '12 at 17:40
    
@LubošMotl, I understand that mass is a property of matter, I used the term "negative matter" just because it's used in the articles that I found. Thank you for the link, I will read it. –  Serg Nov 23 '12 at 17:46
    
Possible duplicates: physics.stackexchange.com/q/18925/2451 , physics.stackexchange.com/q/34115/2451 and links therein. –  Qmechanic Nov 23 '12 at 17:47
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4 Answers 4

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As far as I understand, if it exists, it must be far away from the "positive" matter because of repelling force, so it explains why there is no observations of such matter.

For one, negative mass would still be attracted to positive mass, but the positive mass would be repelled. This would lead to the negative mass "following" the positive mass.

Why is this? The force is a repulsive one. But we also have the fact that $\vec F=m\vec a$. Since one of the bodies has negative mass, it will be attracted.

If there was a body of negative mass less massive (talking about absolute values here) than our positive massed-universe, it would move much faster and eventually "catch up" with ours. If it had the same absolute value of mass, both would keep accelerating and it would never catch up. If it was larger, it would be left behind eventually.

The lack of any large quantities of negative mass in our universe excludes the case of a body of negative mass having caught up with us. The lack of any acceleration of the universe signifies that there isn't any large body of negative mass with absolute value less than or equal to the mass of the universe. So, if there is any large body of negative mass, it has larger mass than our universe and it is separated from our universe.


"all structures that exist mathematically exist also physically" -Max Tegmark.

This is a part of his MAthematical Universe hypothesis. Note that it's just a hypothesis, it isn't backed by much concrete evidence yet.

Despite being completely inconsistent with a common-sense approach and the expected behavior of "normal" matter, negative mass is completely mathematically consistent and introduces no violation of conservation of momentum or energy.

This is true--it lets one create energy out of thin air by introducing a body with negative mass to the system, but this doesn't conflict the principle of conservation of energy as the body has it's own energy become more negative.

Such matter would violate one or more energy conditions and show some strange properties, stemming from the ambiguity as to whether attraction should refer to force or the oppositely oriented acceleration for negative mass.

I'm not too sure about the energy conditions, I'm not strong in General Relativity. But the second half is just about some strangeness attached to it and some confusion regarding terminology (relating to what I explained near the top of this answer).


Finally, vacuum fluctuations (which exist) can have a net negative energy density, so these have "negative mass", in a way. But these aren't easy to harness with current technology.

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Many thanks for the answer. But I don't understand the "negative mass "following" the positive mass" phenomena. If you use positive and negative mass in the universal gravitation formula, the result is negative force. But it's applied on opposite directions for both objects, so the must both repel each other. Why doesn't it happen with particles with opposite electric charges? –  Serg Nov 23 '12 at 18:24
    
@Serg: But, "F=ma". If the m itself is negative, a "repulsive" force leads to an acceleration in the opposite direction. With negative mass, pulling it one way makes it go in the exact opposite direction. –  Manishearth Nov 23 '12 at 18:26
    
can you please give a reference to such explanation? I think it's wrong. Otherwise, positive mass would also suffer from this chase-escape problem ( en.wikipedia.org/wiki/Gravitation_constant) because the force vector is defined towards the other object, and so it's always opposite for them. –  Serg Nov 23 '12 at 18:37
    
@Serg: No reference, it's mathematical. The force of gravity on particle A due to particle B is defined as $\vec F_{AB}=-\frac{Gm_am_b\vec{r_{AB}}}{|r|^3}$ in vector form, where $\vec r_{AB}$ is a vector pointing from B to A. So, if A has negative mass, the force vector on A points away from B. But, due to $\vec F =m\vec a$, the acceleration vector points towards B. On the other hand, for B, the force vector points away from A (as the $\vec r_{AB}$ becomes $\vec r_{BA}$ when you switch), and due to its positive mass, so does acceleration. –  Manishearth Nov 23 '12 at 18:48
    
I don't understand your logic behind "suffer from this chase-escape problem ( en.wikipedia.org/wiki/Gravitation_constant) because the force vector is defined towards the other object, and so it's always opposite for them", could you please be a bit clearer? Or come to Physics Chat and we can discuss this clearly. –  Manishearth Nov 23 '12 at 18:49
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No. Matter must have nonnegative mass for reasons of causality. This follows from relativistic quantum field theory, as it is impossible to define free causal quantum fields (modeling the asymptotic = observable bound states) with negative masses.

Speculations that there might be particles of _mass_square_ smaller than zero (which would then always move faster than light) have been thoroughly discussed and tested in the literature, without any positive evidence. See the section ''What about particles faster than light (tachyons)?'' in Chapter A7: Time and space of my theoretical physics FAQ at http://www.mat.univie.ac.at/~neum/physfaq/physics-faq.html

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I thought tachyons had imaginary mass, not negative mass? –  user56771 Nov 25 '12 at 7:50
    
@user56771: Oh yes, sorry. I was thinking of negative mass square. I'll edit my answer. –  Arnold Neumaier Nov 26 '12 at 9:39
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So far as we know $m \geq 0$ --all observations are compatible with this--.

Mathematically you can imagine negative masses, imaginary masses or many other masses, but this does not mean they are real.

No, negative mass is not consistent with the idea that the total energy of the Universe is zero. This zero of energy is because gravitational energy is negative and in the free-lunch cosmology compensates the positive energy associated to matter giving a zero total energy. Zero energy does not imply zero mass or vice verse; for instance photons have zero mass but positive energy.

The quote from Max Tegmark looks particularly misguided to me. In his lectures on physics Feynman explains the difference between physics and maths.

How do you know that a negative mass "introduces no violation of conservation of momentum or energy"?

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"How do you know that..." -I don't know that. I was looking for information on this topic and found those statements in Wikipedia (you can see a link there). So, I asked this question here. Thank you for the answer. –  Serg Nov 23 '12 at 17:54
    
Ok I believed you had additional info. Yes Wikipedia says so (because someone wrote), but it does not give any demonstration/argument/reference. Thank you. –  juanrga Nov 23 '12 at 18:12
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As far as I understand, if it exists, it must be far away from the "positive" matter because of repelling force, so it explains why there is no observations of such matter.

Negative mass(energy) is accelerated in the direction of positive mass(energy), and positive mass(energy) is accelerated in the direction to be far away from negative mass(energy).

But,

1) If the absolute value of positive mass is bigger than that of negative mass, they will meet within finite time (attractive effect)

2) If the absolute value of positive mass is smaller than that of negative mass, the distance between them will be bigger, and they cannot meet (repulsive effect).

I made simulation video on negative mass's motion

http://www.youtube.com/watch?v=MZtS7cBMIc4 : refer to 00:00 ~ 02:40s

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protected by Qmechanic May 19 '13 at 20:15

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