$2\pi\omega \cdot A = v_{max}$ so try $v_{max}=\lambda \omega=A \cdot 2\pi\omega$. Solve for what you want, $A=\frac{\lambda}{2\pi}$ where $\lambda$ is different for each wave, as I enumerated in the comments, $\lambda_A=2$m and $\lambda_B=4$m.
I hope I answered your question right from what you're telling me. I will stress that in order to get a solid response, post your FULL question in clear terms and make sure you post everything you know and tried. Try to focus it down to conceptual questions. We want to help, but we also don't want to explicitly do your homework. Hope this helps, cheers.