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Imagine we have 2 capacitors of capacitance $C_1$ and $C_2$ respectively. One is charged with charge $Q_1$, and the other is not charged.

Now we connect them in series as shown in figure:

enter image description here

What is the charge now on every capacitor?

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I'm sure this has been asked, and answered, before. Try searching the site for something obvious like capacitor. I think David was a bit hasty in closing your question as "too localized" because it seems a reasonable question, but it would have been closed as a duplicate anyway. – John Rennie Nov 7 '12 at 18:11
Aha, found it. See physics.stackexchange.com/questions/21418 – John Rennie Nov 7 '12 at 18:16
@JohnRennie Yeah very harsh, I was surprised by the reaction. Anyway, thanks a lot for your trying to help, but that link is for an ambiguous question different, the answer also required that same potential difference is maintained across the capacitors. In my question there is no battery anywhere as shown in figure. It is not clear how the charge from one capacitor will distribute between the two of them. Looks like there is no sufficient information to know the answer (and no interested moderators to keep the question alive either) – Revo Nov 7 '12 at 18:30
Oops yes, in that question the capacitors are connected in parallel not series. However I'm sure I have seen a question that was very similar to yours. – John Rennie Nov 7 '12 at 18:49
Aha 2! see physics.stackexchange.com/questions/30120. This is definitely a duplicate of your question. – John Rennie Nov 7 '12 at 18:55

closed as too localized by David Zaslavsky♦ Nov 7 '12 at 17:34

This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, see the FAQ.