According to Bogolubov postulate (various texts name it differently) in Non-equilibrium thermodynamics, the number of needed parameters to describe our system is decreasing with time, and finally at infinity, once our system reaches its equilibrium state, we will need only the usual three thermodynamic parameters $T,V,N$ to define the state.
Ok, this seems to be very logical, however, how does entropy fit in there? Generally speaking we can say that entropy describes the disorder in our system, and the higher the entropy, the less order we have, and more disorder means less symmetry in the system. (Or is this statement wrong?)
And when a system has high symmetry, we need less parameters to describe it, which uncovers a contradiction than I can't understand:
A system has reached equilibrium state, when the system's entropy reaches its maximum (we are talking here about isolated systems only), but maximum entropy means maximum disorder, maximum disorder means the need for a lot of parameters to describe it due to luck of order. But that is the opposite of what the postulate above states.
So where is the mistake in this statement? (I asked my professor and he answered that defining entropy in a non-equilibrium state is, for now, an open question but I think that the answer should lie somewhere else...) (in case there is really some relation between Entropy and Symmetry, please provide some math how this is accomplished)