# What is the gravity at the center of the Earth? [duplicate]

Possible Duplicate:
Would you be weightless at the center of the Earth?

Supposing there is a cavity at the center of the Earth, what is the gravity there? What will be its direction and intensity? Will a body be attracted toward the center of mass of the Earth?

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## marked as duplicate by Qmechanic♦, Alan Rominger, David Z♦Oct 25 '12 at 16:10

This question was marked as an exact duplicate of an existing question.

Possible duplicate: physics.stackexchange.com/q/2481/2451 – Qmechanic Oct 25 '12 at 15:40
'bout zero in the middle – Lucas Oct 25 '12 at 15:53

The gravitational field a distance $r$ from the center of a solid sphere with uniformly distributed mass is $$g\left(r\right) = -\left(\frac{4}{3} \pi G \rho \right) r,$$ where $\rho$ is the mass density of the sphere, and $G$ is the gravitational constant. The value of the field at the center is $$g\left(0\right) = 0.$$ The actual field at the center of the Earth will not be zero, however, because the Earth is not a perfect sphere, does not have uniform density, and is not the only object in the universe.