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Just curious, can anyone show how the integral and differential form of Maxwell's equation is equivalent? (While it is conceptually obvious, I am thinking rigorous mathematical proof may be useful in some occasions..)

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Are you familiar with Green's and Stoke's theorems? – Jerry Schirmer Oct 9 '12 at 16:48
@JerrySchirmer yes. (and I just want to see more rigorous proof; conceptually, this is somehow obvious, I guess.) – Paul Reubens Oct 9 '12 at 17:05
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Just integrate the divergences and the curls using green's and stokes theorems and you will get the integral form. – Prathyush Oct 9 '12 at 19:16
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Comment to the question(v2): Could you narrow down which part of the standard textbook treatment you don't find rigorous? – Qmechanic♦ Oct 9 '12 at 22:36

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