Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

Quasiparticles in spin liquid will no longer be the representation of symmetry group. So when group elements act on quasiparticles, there will be some phase factor. For example, in $\pi$ flux state, $T_xT_y=-T_yT_x$, which means if we move the quasiparticle around a lattice, and there will be a minus sign. However, because the quasiparticle are always emerging in pairs, when we move one quasiparticle, it cannot be avoided that we will also move another. In this case, the phase factor (minus sign) will be cancelled out. If we wants to move only one quasiparticle, the symmetry operator must be a local operator. But what does it mean for local operator of the global symmetry? How can we measure the PSG in general cases?

share|improve this question
add comment

1 Answer

This question is a very good question, which is partially addressed in my original article on PSG:

arXiv:cond-mat/0107071 Quantum Orders and Symmetric Spin Liquids

arXiv:cond-mat/0110397 Quantum Order: a Quantum Entanglement of Many Particle

arXiv:cond-mat/0202166 Gapless Fermions and Quantum Order

One can partially and indirectly measure PSG by measure the spectrum function of spin correlation (which is a two spinon spectral function). In π flux state, $T_xT_y=−T_yT_x$, the lower edge of the spectral function is repeated in 1/4 of BZ. (See Fig. 11 of arXiv:cond-mat/0107071, for example)

share|improve this answer
add comment

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.