One of the first assumptions, when introducing the Lagrangian and Hamiltonian in an undergraduate course on QFT is $$ \phi(x)=0\,\text{on the boundary} $$ and this is widely used in many situations (e.g when calculating a surface integral on the boundary). Is there a physical reason for such assumption?
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In general, boundary conditons must be adapted to the real situation. Zero boundary conditions are just for the sake of simplicity. But they are realistic only when the field is really zero for some definite reason. If the boundary is at infinity, zero boundary conditions means that everything of interest happens in a finite domain and cannot be noticed from far away. If this is really the case, these boundary conditions are appropriate. In particular, one needs zero boundary conditions for square integrable states. But scattering requires different boundary conditions as something moves across space and time from infinity to infinity. The corresponding scattering states are not square integrable. |
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