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Show that the Hamiltonian operator $\hat{H}= (\hat{p}^2/2m)+\hat{V}$ commutes with all three components of $\vec{L}$, provided that $V$ depends only on $r$. (Thus $H$,$L^2$, $L_z$ are mutually compatible observables). ($\vec{L}$ is $\langle L_x, L_y, L_z\rangle$.)

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closed as off-topic by DavePhD, Brandon Enright, John Rennie, JamalS, Danu Jun 1 '14 at 8:36

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1 Answer 1

Show that $L_x$ commutes with $(x^2+y^2+z^2)$ and use it to prove it commutes with $r$. Then it follows that $L_x$ commutes with any function of $r$ or $1/r$ and therefore with $V(r)$. Then show that $L_x$ commutes with $(p_x^2+p_y^2+p_z^2)$. So $L_x$ commutes with $H$. $L_y$ and $L_z$ follow by symmetry.

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