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When describing a black hole evaporation in the hawking black body radiation it is usually said that is due to a virtual photon pair, is it this what happens? And what is virtual photon pair, does the photon has anti particle or it is its own ? I am not looking for a deep theory, just the general picture.

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No, this is a confused picture . There are no virtual photon pairs though there are virtual photons interacting with virtual particles. It is the virtual particle_antiparticle pairs that are used to explain how radiation can leave a black hole, one of the pair leaving the other absorbed. The Hawking black body radiation comes from a computation that splits the solutions of Maxwell's equations into positive frequency and negative frequency: nothing to do with photon pairs ( the photon is its own antiparticle). I hope somebody with better background than I replies to your question. –  anna v Sep 18 '12 at 18:14
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As Anna says, while it's commonly stated that Hawking radiation is due to one member of a particle anti-particle pair falling through the event horizon, this is nothing more than a metaphor and it's not actually what happens.

I actually answered this question is some detail in Black holes and positive/negative-energy particles, but I suspect this answer may be overly complex. The phenomenon is related to the curvature of spacetime. Have a look at my answer and if you want to explore any of the points I discuss post another question and I'll help if I can.

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