This question regards Ewings molecular theory of magnetism
I.) Ewing's molecular theory of magnetism describes every magnetic substance as being a collection of dipoles that are initially in a state where there is no specific and uniform orientation as a result of the application of a magnetic field and because of this the net magnetic field strength of the substance becomes zero. Now, let us place a magnet close to this object. The magnetic field passes through this object (assume the substance is ferromagnetic), and the dipoles orient themselves in the direction of this magnetic field. Now due to magnetic field induction, the substance has gained magnetic properties. However so infinitely small, let us assume a certain interval of time had passed for the dipoles to orient themselves. Let us record this time and keep it aside for future reference. Now let us melt down this exact same substance used in our experiment and once again pass the very same magnetic field through the molten substance. Again let us record the time taken for the dipoles to orient themselves. Let us compare the time intervals we have recorded. Now my question is this: since the substance was originally a solid, the electrostatic force of attraction between adjacent molecules would be high; so magnetic field strength would have to be significant and would take some time to force the dipoles into its direction. Then we remove this field and supply heat energy to this substance. The individual kinetic energies of the molecules slowly overcome the electrostatic force of attraction between the adjacent molecules and the substance changes into a liquid. Since the force of attraction is significantly lesser than it was as a solid, if we were to apply a similar magnetic field through this medium, would the time taken to orient the dipoles be different than when we passed the field through the solid?
I hope you can answer the question for me.
Tell me more
×
Physics Stack Exchange is a question and answer site for
active researchers, academics and students of physics. It's 100% free, no registration required.
|
|
|||||
|