# How does the Feynman's $i\epsilon$-prescription make the Feynman propagator causal?

The Feynman propagator is non-vanishing outside the light cone, but still manages to be in accord with causality. How is this achieved? What does the $i\epsilon$-prescription have to do with this?

-

The $i\epsilon$ prescription is so that you get the time-ordered product of operators, which is the correct interpretation of such an expectation value from the perspective of the path integral.