# how does accelerating charge produce Electromagnetic radiation? [closed]

Suppose an electron is accelerating along $x-$axis. How does it produce electromagnetic radiation?

Which of Maxwell's equation comes in play and how do I derive the wave equation from it?

For oscillating charge the emerging EM wave is explained in this video. What kind of EM wave emerge out in this case (not oscillating but only accelerating in one direction)?

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## closed as not a real question by dmckee♦Aug 23 '12 at 1:50

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

Hi there testuser. What does "in which direction does it travel with respect to it's direction of travel" mean? And would you like to be specific about one single question - I think you've got several questions all bundled into one there. – EnergyNumbers Aug 20 '12 at 11:25
In case of Oscillating charge, it is easy to visualize the electromagnetic radiation emerging radiation. If the charge is not oscillating but accelerating how does what kind of electromagnetic radiation emerges? – hasExams Aug 20 '12 at 16:34
You still have "in which direction does it travel with respect to it's direction of travel", which is horribly unclear because you have two "it"s the antecedents of which are ill-defined. – dmckee Aug 20 '12 at 16:41
In any case what part of this don't you understand? The field configuration depends on the charge configuration which you have defined as accelerating so there is a $\frac{d^2E}{dt^2}$. Is the problem conceptual or with bashing through the math? Finally, would you be satisfied with a more complicated charge configuration if it developed a simpler field configuration (the usual first example is the sinusoidal dipole, after all). – dmckee Aug 20 '12 at 16:50
@testuser, have you perused this? – Alfred Centauri Aug 20 '12 at 21:02