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Gauss's law for Gravitation:

$$\int g\cdot \mathrm{d}S=4\pi GM$$

where $g$ is the gravitational field and $S$ is the surface area.

Am I correct?

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1 Answer 1

up vote 5 down vote accepted

$\oint_{\partial V} g\cdot dS=-4\pi GM_{enclosed}$ where integral is surface integral over a closed surface.

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This is what the Wikipedia page has, but they write $dA$ instead of $dS$ and write a double closed integral. I'm not a stickler about calculus grammar, but the symbology seems to be the central confusion of the question. –  Alan Rominger Jan 16 '13 at 13:48

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