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Can the gamma ray bursts connected to a new supernova prevent the black hole from forming?

Quoting the abstract of the linked reference "...has become clear that probably all long GRBs are associated with type-Ic supernovae resulting from massive stars that suffered substantial mass loss...".

If enough mass is converted into radiated energy then the condition for BH formation can vanish?

Edit Add:
Due to the lack of the expected neutrinos, the IceCube Experiment puts to trash the connection of GRB and SNe.
quoting Cosmic Varience:

More recently, a consensus had grown up that GRB’s (as they are called) are associated with intense beams of particles created by newly-born supernovae. That’s a model that seems to fit most of the data, anyway, and it also makes a pretty good prediction for the production of associated neutrinos. But a new paper by the marvelous IceCube experiment has thrown a spanner into the works: they should have been able to see those neutrinos, and they don’t.

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Sometimes it is necessary to rely on references in order to ask a question, this is not the case. You look like you didn't even try to formulate your question. (oh, and 23% of your words are abbreviations. =P) –  Bruce Connor Jan 19 '11 at 14:17
    
part of the abstract of the reference linked in the question "...has become clear that probably all long GRBs are associated with type-Ic supernovae resulting from massive stars that suffered substantial mass loss...". If enough mass is converted into radiated energy then the condition for BH formation is, or is not, eluded. –  Helder Velez Jan 19 '11 at 14:35
    
cool, just paste that inside your question. :-) –  Bruce Connor Jan 19 '11 at 14:43
    
Earlier comment was in error. Thanks for the link. –  dmckee May 17 '12 at 0:42

3 Answers 3

Let me start with what a long gamma-ray burst (LGRB) is. The current model says that GRBs are observed when the core of a rapidly-rotating massive star collapses into a black hole (BH). Stellar material that is accreted swirls around the BH, forms an accretion disk and launches polar jets. If the jets are pointed at us, we observe a brief (in astronomical terms), bright, relativistically blue-shifted emission: a LGRB. (Long only in the sense that they are longer than "short" GRBs, which last seconds and are probably caused by something different.)

So, the first problem with saying that the formation of a GRB is that the GRBs emission requires a BH. That is, if there's no BH, there's no GRB. The answer to your question is no.

The mass loss that you describe occurs in the massive progenitor star before core collapse. So while it's true that a 60$M_\odot$ star loses its hydrogen and helium envelopes (the absence of helium or hydrogen lines in the supernova spectrum is why it's of Type Ic), at the point of core collapse there is still about 20$M_\odot$ of stuff in the star available.

Finally, this mass is not lost because it is converted into energy. Instead, it's because the radiation produced by fusion in the core exerts a force on the envelope that, where stronger than gravity, drives material off the surface. These are known as stellar winds.

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In my question I added about the IceCube experiment that invalidates the SNe connection (the neutrinos are missing). –  Helder Velez May 16 '12 at 23:46
    
Well, it invalidates a big piece of the existing theory of these things, anyway. –  dmckee May 17 '12 at 0:43

It is impossible to get rid of black holes by this mechanism, because with a sufficiently large quantity of matter, one can form a horizon with no large gravitational fields at all. If this method works to prevent certain astrophysical collapse scenarios, it cannot prevent hypothetical collapse scenarios where no gravitational field becomes large at the moment of collapse.

The key point is that the mass of a black hole forming amount of material is proportional to the radius of the black hole. This means that if you have a constant density $\rho$ in a square of side-length R, even if the density is low, a black hole necessarily forms approximately when the Schwartzschild radius of the mass is greater than the side-length.

$$ {GM\over c^2} = {G\over c^2} \rho R^3 = R$$

Solving for R:

$$ R = c\sqrt{1\over G\rho}$$

for the density of water, $\rho=10^3 {\mathrm{kg}\over \mathrm{m}^3}$, the radius is about 10$^9$ km, so a light-day radius sphere of water will collapse, with no unusual x-ray phenomena, because the gravitational field is never strong before the event horizon forms.

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We assume that under extreme gravitational pressure the star must collapse into a BH because there is no known physical mechanism that can get rid of the star matter too much.

Theoretical models of GRBs, and associated SNe, are struggling against the observations (Gamma Ray Bursts: back to the blackboard by Maxim Lyutikova).

We have for granted that the BHs are an integral part of GR. However, GR survives even if they do not exist. The link referenced in the question make me wonder: Is it the case that BHs may not exist?
My answer is yes, provided that the energy of the particles becomes radiation (EM X-rays, gamma-rays, ..) before the star collapses. $E=mc^{2}$ allows it but the SM does not. I'm optimistic and I have to me that the LHC will teach us a lot. We must be humble and pursue other routes.

The issue of singularities in space/time is, imo, very difficult to accept philosophically and physically and I feel better with the hope that they do not exist. The future of physics may be different than we expected.

Mankind has the hopes placed in physics because it is a theme central to our collective future. Thankfully, the GUT is not there just around the corner and that's good for the physicists of the future. ;-)

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Admittedly I'm way way way out of my league here, but I have trouble imagining more than afew percent of rest mass being lost in this manner. If so ot's only likely to matter in marginal cases. Unless you can limit the iron core mass that begins the implosion, such that only a very limited mass range of condensed matter cores can be created. And then don't we have observational evidence of roughly ten solar mass compact objects?.... –  Omega Centauri Mar 8 '11 at 4:20
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There are astrophysical black holes that have actually been observed, though. How else are you going to explain the stellar velocities near the center of the milky way? Or objects like Cygnus X-1, which have radiation profiles consistent with black holes, and observed masses too large to be neutron stars? –  Jerry Schirmer Mar 8 '11 at 4:29
    
@Omega Centauri it is the SM of particles that does not offer any way for the rest mass of barions be transformed in EM energy that could escape from the star at c speed under the pressure of the gravitational field. The model of particles of Douglas Pinnow presented in his book 'Our Resonant Universe' is EM based. My hope is some model will offer one way out (there are recent news that SM, and SUSY, are in trouble). There are strong feelings that theoretical work is to be done. –  Helder Velez Mar 8 '11 at 23:15
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I don't believe there is any serious discussion about black-holes not existing in some form. It is a stable solution to the E.F.E.s and there is extremely strong observational evidence from active galactic nuclei and galaxy formation. As the old saying goes, extraordinary claims require extraordinary evidence. Whether or not a supernova results in one doesn't have to be turned into an existential argument about black holes in general. –  Benjamin Horowitz Jul 6 '11 at 2:34
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You are simply stating that matter never enters the black hole, that only the exterior makes sense. This is a dual point of view, the exterior picture, but it doesn't stop the interior from being observed by an infalling observer, and it isn't so good to state it this way. –  Ron Maimon May 17 '12 at 0:29

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