# Conjugate Transpose of Hamiltonian Matrix

$$i\hbar \frac{dC_{i}(t)}{dt} = \sum_{j}^{} H_{ij}(t)C_{j}(t)\tag{1}$$

where $C_{i}(t) = \langle i|\psi(t)\rangle$ and $H_{ij}$ is hamiltonian matrix.

However, what is obscure to me is the way to deduce

$$H^*_{ij} = H_{ji}\tag{2}$$

in the notes.

They explain (2) as

(2) follows from the condition that the total probability that the system is in some state does not change. If you start with a particle then you have still got it as time goes on. The total probability of finding it somewhere is

$$\sum_{i}^{}\left|C_{i}^2 \right|$$

which must not vary with time. If this is to be true for any starting condition $\phi$, then (2) must also be true.

I cannot understand the relationship between the total amplitude and (2).

Well.. though I omit other contents/derivative of (1) in the notes to simplify my question, it will be very helpful for me if you figure out the explanation of the notes above.

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Work out the derivative of your formula for the total probability (after changing the faulty $|C_i^2|$ to the correct$|C_i|^2$), using (1) to eliminate all derivatives. Then the conclusion should stare into your eyes.
@true: Not the amplitude is constant in time, but the squared absolute value. The latter is the sum of individual squared absolute values, which represent (Born interpretation) the probability that upon measuring, the $i$the result is obtained. In an ideal measuremnt, some result must be obtained, which means that these probabilities must sum to 1. – Arnold Neumaier Jul 25 '12 at 10:15