The correct equation, to represent the physical system, must give an answer that is bounded by the physical extremes of t = 0 and t = x, i.e.:
$\frac{kq^2}{Kx^2} < F < \frac{kq^2}{x^2}$
The lower value is when t = x and the upper value is when t = 0.
I'm thinking that we need to find an effective relative dielectric constant to use over the distance x.
$F = \dfrac{kq^2}{K_{eff}x^2}$
Given the bounds above, I'm thinking a kind of weighted harmonic mean might work.
$K_{eff} = \dfrac{x}{(x-t) + \dfrac{t}{K}}$
Note that when:
$t = 0, K_{eff} = 1$
$t = x, K_{eff} = K$
Anyhow, if you stare at this a bit, you'll see that the force, as desired, decreases as t increases and that the formula reduces to the bounds above for t = 0 and t = x.