I've noticed a motionless kingfisher over a lake looking for prey and wondered what amount of energy does a bird, weighing 0.15kg, require to hover for 15s?
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If the mass of the bird is M, and it is modelled as a fan which is pushing air to velocity v downward constantly and continuously, then in any unit of time $dt$ it must push an amount of air down on average to get $Mgdt$ up-momentum. This means that the mass dm of the air it pushes down to velocity v in time $dt$ is such that it's momentum is $dm v = Mg dt$, so the amount of air pushed down per unit time is $$ dm = {Mg\over v} dt $$ The energy this air gets, assuming the air starts at rest is $$ dm {v^2\over 2}$$ So the work done is $$ {dE\over dt} = {Mg\over v} {v^2\over 2} = {Mgv\over 2} $$ This assumes that all the air accelerated by the bird dissipates its energy, so that the energy is lost forever. This is not accurate, and the above is a simple estimate. For a bird of mass .1 kg, g=10 m/s^2, v=1 m/s (assuming the wing is 10 cm from top to bottom of the stroke and flaps 20 times a second), the work required is 1 Watt. The parameter v is determined from the wing-speed, and the total mass of air you push per wing-flap is the area of the wing times the density of air times the period of a wing-flap. The gives a relation between the size of the bird and the wing-flap frequency. This is order of magnitude only, and it is more valid the more turbulent the air-flow is. |
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I agree with dmckee's comment above. I would just like to add that hovering motionless birds most probably use ascending air streams (unless when they descend slowly). Pretty much the same happens with gliders: they use ascending streams to go up or they descend slowly. |
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