# Taylor approximation of e(v) [closed]

Relativistic mass $\displaystyle m(v)=\frac{m_o}{\sqrt{(1-(v/c)^2}}$

$m_o$ = mass of object measured at rest
$c$ = speed of light ($3\times 10^8\;m/s$)
$v$ = speed

If the total relativistic energy of an object is given by $E=mc^2$, then find the second-order Taylor approximation of $E(v)$. The zeroth-order term is called the "rest energy." What is the second-order term usually called?

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@ZevChonoles I agree. –  Alex Becker May 12 '12 at 21:12
I'm going to migrate this question to the physics.SE site. There will be a link that appears below the question here that you can follow to the new location of your question. If you need help associating an account on physics.SE, you can flag your question for moderator attention, and someone over there will help out. –  Zev Chonoles May 12 '12 at 23:16
Hi user28710, and welcome to Physics Stack Exchange! This is a site for conceptual questions about physics, not general homework help. If you edit your question to show your thought process in working on this problem, and ask about the specific physics concept that is giving you trouble, I'll be happy to reopen it. See our FAQ and homework policy for more information. –  David Z May 12 '12 at 23:31