# Electric circuit. Slight problem with the sign on voltages

Translation first!
The figure shows an electric circuit.
a) Use Kirchhoffs 2.law on the part-circuit abed and show that $I_3$ = 0,50A.
b) Explain that $I_2 + I_5 = 2,0A$. Use Kirchhoffs 2.law on the part-curcuit befc to find another equation with $I_2$ and $I_5$ as unknows. Solve the set of equations.
c) Find $I_1$ and $I_4$.
d) Find the resitance of R.

a) Assume clockwise rotation of circuit. That makes 8v positive and 5,5v negative. 8-5,5=2,5v. This would be the V over the resitance at $I_3$. $\frac{2,5v}{5 ohm} = 0,5A$ I think this is correct.

b) My problem is that I can't seem to find the equation properly. If I assume a clockwise current, that makes V at $I_3$ negative. And V at $I_2$ positive and V at $I_5$ negative.
$-2,5 = 5I_2 - 2,5I_5$
Solution in the book is $-2.5 = - 5I_2 + 2,5I_5$ with $I_2 + I_5 =2$ It gives $I_2=1$ and $I_5 = 1$
My logic is wrong, but wrong how?

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Fixed it myself. The book defined the 2.law in a stupid way. Wiki helped me out. – Algific May 5 '12 at 12:04
Hi Algific, and welcome to Physics Stack Exchange! It would be great if you write an answer describing what you were doing wrong and the solution you found, and perhaps even describing what's wrong with the book's description of the 2nd law. We encourage self-answers here. (You may have to wait a few hours before doing so because of technical measures imposed by the system for new users.) – David Z May 5 '12 at 15:26