Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

I am trying to find a formula that will enable me to calculate the illumination of the moon down to one thousandth of a percent, given that the Gregorian year, month, day, and hour is known. Can anyone help me with this formula?

share|improve this question
2  
Is there a specific date you're interested in? My understanding is there was generally non-uniform adoption of the Gregorian calendar in many countries, and perhaps some anomalous corrections to the calendar at various times and places, so your answer likely depends on what you want to use the answer for. –  Ryan Budney Sep 22 '10 at 21:12
    
I'll need to refer to my copy of Meeus to be sure; the problem is that the secular corrections are probably going to throw a wrench on things. Would you happen to have an up-to-date ephemeris on you? –  J. M. Sep 22 '10 at 22:12
    
Ryan: I am mainly wanting to use the calculations for dates present and in the future...historical would be nice, but I don't have to have that. –  Robert Fleming Sep 23 '10 at 0:50
    
J.M.: I will show my ignorance by saying that I do not know what an ephemeris is. I am a little familiar with Meeus, but I don't have his books. –  Robert Fleming Sep 23 '10 at 0:51
    
Here ya go, for your enlightenment: en.wikipedia.org/wiki/Ephemeris ; JPL keeps their collection in ssd.jpl.nasa.gov/pub/eph/planets ; I still haven't finished reviewing the literature on this, but it seems deriving illumination from the exact date is not that easy. –  J. M. Sep 23 '10 at 2:07
show 3 more comments

2 Answers

I'm unsure what is meant with

[...] calculate the illumination of the moon down to one thousandth of a percent [...]

Assuming that you are trying to determine if a certain point on the lunar surface is illuminated or not, I could possibly give an approach for that - I've done that within my Master's Thesis, since one of my tasks is the development of a Moon surface illumination simulation software. (If you are interested in this topic, first results can be seen here; the thesis itself will be published in spring 2012.)

The required astrodynamical calculations for this purpose are quite complex; I don't believe that a single equation can be derived. For high accuracy astrodynamical calculations an extensive set of differential equations needs to be considered and evaluated - according to the level of accuracy which is needed.

Hence, I would advise to use an external library like the NASA NAIF SPICE toolkit, which is available for many environments (C, C++, Matlab, IDL, Fortran). This way, you have to write a short program in one of those languages.

Use SPICE to calculate the Sun's position at a certain point of time (your Gregorian date is the input) w.r.t. the Moon's Mean Earth/Polar Axis reference frame (ME/PA). This reference frame is defined bodycentric for the Moon. Its origin is the lunar center, z-axis is the polar axis, x-axis is the mean Earth direction. This way, the location (0° N, 0° E) on the Moon's surface, expressed by the pair (lat, lon) (latitude and longitude), will be at $(r, 0, 0)$ in the ME/PA reference frame, whereas $r$ is the lunar volumetric mean radius. More examples: $(0^\circ\,\text{N}, 90^\circ\,\text{E}) \mapsto (0,r,0)$, $(90^\circ\,\text{N}, 0^\circ\,\text{E}) \mapsto (0,0,r)$, $(0^\circ\,\text{N}, 90^\circ\,\text{W}) \mapsto (0,-r,0)$.

Knowing the Sun's position in this frame, you are able to determine whether a sunray will hit the given surface point or not by using a simple ray tracing algorithm.

Note: This neglects possible shadow occultations caused by the lunar topography. If such considerations are necessary in your case, there is likely no simple solution, as you must maintain an entire lunar digital elevation model.

share|improve this answer
add comment

I let the programmers of my planetarium software do all the heavy lifting for me with questions like this. I use Starry Night myself, and have come to trust the answers it gives me. If you insist on doing it yourself, Jean Meeus' books are the place to go.

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.