# Flux if there were only one type of charge in the universe

The Question was:

If there were only one type of charge in the universe, then:

• $\phi = \oint \boldsymbol{E}\cdot \partial\boldsymbol{A} \neq 0$ on any surface.
• $\phi = \oint \boldsymbol{E}\cdot \partial\boldsymbol{A} = 0$ is the charge is outside a surface.
• $\phi = \oint \boldsymbol{E}\cdot \partial\boldsymbol{A}$ will not be defined.
• $\phi = \oint \boldsymbol{E}\cdot \partial\boldsymbol{A} = \frac{q}{\epsilon_o}$ if the charge is inside the surface.

The answers were given as option second and the last one. (Gauss' law statements)

How?

-
Hi The-Ever-Kid and welcome to Physics Stack Exchange! Our homework tag is for more than actual homework questions, so this does qualify. To improve your question, consider this: what exactly is confusing you about why these particular options are the right ones and the others are wrong? –  David Z Apr 28 '12 at 7:31
If there was only one kind of charge then there would be no nutrality in the universe i.e no bipolarity . if that was the case the where would the positive test charge go when it is repelled by the source charge . i mean i saw this video on YouTube where the teacher said that the field lines of an isolated positive charge go to infinity where the opposite charge is present so as to ensure conservation of charge. but here theres no negative charge so where would the field lines go to. –  The-Ever-Kid Apr 28 '12 at 8:20
This is indeed completely ridiculous--- the "what if" has no answer, and this is a problem of "read my mind". –  Ron Maimon May 1 '12 at 13:40
@RonMaimon Meaning? –  The-Ever-Kid May 12 '12 at 20:00