Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

A pendulum clock beats every time the bob passes through its lowest point. What must be the length of the pendulum at a place where g= 32.0 ft/s^2? If the clock is moved to a point where g=31.0 ft/s^2, how much time will it lose in one day?

share|improve this question

1 Answer 1

Use the formula for mathematical pendulum

$$T_0 = 2 \pi \sqrt\frac{l}{g}$$

where $T_0$ is period of oscillation. Clock beats every $T_0/2$ time, since bob passes through the lowest point twice every full swing.

I am amazed that someone is still using feet...

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.