# Is fire plasma?

Is Fire a Plasma?

If not, what is it then?

If yes why, don't we teach kids this basic example?

UPDATE: I probably meant a regular commonplace fire of the usual temperature. That should simplify the answer.

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Home experiment: put a strong (i.e. rare earth) magnet on the end of a pole and see if it affects the behavior of a flame more than a pole without the magnet does. Why? Because the magnet will affect ions and free electrons in motion much more strongly than neutral components. – dmckee Apr 9 '12 at 20:56
As far as I know ordinary flames are not significantly ionized: they're just hot gas with chemistry going on in them. But I'm not certain enough to post an answer, so don't quote me. – dmckee Apr 9 '12 at 21:18
A similar question is the basis for a recent project in science communication. Check it out: flamechallenge.org – Greg P Apr 10 '12 at 2:20
More on what fire is: physics.stackexchange.com/q/9708/2451 – Qmechanic Apr 10 '12 at 4:36
@dmckee What about a simpler experiment of conductivity: can a circuit be closed with a flame? If there is plasma there will be free electrons and ions so two conducting leads to a flame ccould be closing a circuit and current would appear. – anna v Apr 10 '12 at 4:49

Broadly speaking, fire is a fast exothermic oxidation reaction. The flame is composed of hot, glowing gases, much like a metal that is heated sufficiently that it begins to glow. The atoms in the flame are a vapor, which is why it has the characteristic wispy quality we associate with fire, as opposed to the more rigid structure we associate with hot metal.

Now, to be fair, it is possible for a fire to burn sufficiently hot that it can ionize atoms. However, when we talk about common examples of fire, such as a candle flame, a campfire, or something of that kind, we are not dealing with anything sufficiently energetic to ionize atoms. So, when it comes to using something as an example of a plasma for kids, I'm afraid fire wouldn't be an accurate choice.

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I don't think so--- the fire itself has a significant proportion of ionized atoms, it is not just hot gas, because the glow is due to the recombination in particular lines which are dependent on the chemical emission lines (you can see this in burning salt). – Ron Maimon Apr 10 '12 at 4:01
@Ron, are you sure it's recombination or maybe it's just transitions? I don't have a strong opinion on that, the reason I ask is that I think this might make the difference between fire and plasma (if any). – Lev Levitsky Apr 11 '12 at 14:54
@LevLevitsky: I am not sure--- it might be just outer shell transitions--- but once you ionize once, it is so much easier to eject the electron out teh atom. I am confused now on the issue--- I have found sources going both ways. I though the best thing would be to test conductivity, but somebody did, and said he didn't see conductivity (but this might be a low conductivity), the sharp boundary of the flame, the lack of gradual cooling, suggests that it is some sort of steady-state phase of combustion. It is hard to say if steady state non-equilibrium stuff is this or that. I don't know. – Ron Maimon Apr 11 '12 at 15:35
@Ron, even cold gas is glowing, just in infrared spectrum. – Anixx Sep 4 '12 at 16:53
@Anixx: Of course, but why the sharp change in color? Does the gas abruptly cool down? Why there? I figured it was ionization transition of some kind, but I am not sure anymore. – Ron Maimon Sep 4 '12 at 20:49

There's this very interesting demonstration on "1veritaserum" channel on youtube involving a candle, two large metal paddles and 1000 volts of electricity. check it out:

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fire is not a plasma if heated with high temperature it can become plasma

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Welcome! Typically one-line answers should be avoided and more information provided. – tpg2114 Dec 9 '12 at 8:16

Fire is a plasma. There are two kinds of plasmas: hot plasmas relevant to astrophysics or fusion are indeed a mixture of totally ionized gas. In cold plasmas ( northen lights, Neon tubes,flamme) the ionization degree is less than one but the mixture typically exhibit collective behaviour and a zoo of waves one do not encounter in gases. The most famous is the plasma oscillation and the Alfven wave but they are many others. poorsod's calculus assume the ionization takes place between n=1 and n=infinity. In reality, the atoms are first excited by collisions, their electrons jump on higher n until their bounding energy is lower than thermal energy of free electrons. For 0.1 eV more than 99% of the atoms are ionized (I did work on a computer model to analyze this problem). Though the equilibrium Saha approach is known to be false (the electron distribution function is not Maxwellian), you can get a preety good idea of the problem if you split your neutral atoms population into atoms in the fundamental, n=2, n=3, etc.. and use Saha equation for each population.

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interesting, can other people please confirm this too? – daniel.sedlacek Sep 7 '12 at 1:35
I am sorry, as mentioned by @Mitchell Fire is generally not plasma. it rare for fire to be plasma. A single electron or ion or few of then dose not qualify for being plasma, it has to gather in sufficient amount so that it can show collective behavior. – Samir Chauhan Jan 4 at 8:33

Back of the envelope calculation:

The Saha equation for a Hydrogen plasma says

$$\frac{N_i^2}{N_H} = V \left(\frac{2 \pi m_e k_b T}{h^2}\right)^{3/2} \exp\left(\frac{-R}{k_b T}\right)$$

where $N_i$ is the number of ions, $N_H$ is the number of Hydrogen atoms, $V$ is the volume of the plasma, and $R$ is the Hydrogen ionization energy (13.6eV).

Defining the degree of ionization $\xi = N_i / N_0$, where $N_0 = N_i + N_H$ is the total number of atoms in the system, this can be written

$$\frac{\xi^2}{1-\xi} = \frac{V}{N_0} \left(\frac{2 \pi m_e k_b T}{h^2}\right)^{3/2} \exp\left(\frac{-R}{k_b T}\right)$$

A candle burns at 1000 Celsius, and the flame has a volume of around 1cm^3, with probably 10^20 atoms in the flame. For simplicity, let's assume it's mainly Hydrogen in the flame (the ionization energy of other elements is of the same order of magnitude anyway, so we won't be far off). Then I make the right hand side of the equation (we'll call it $f$) to be around 10^-54. Then we can solve $\frac{\xi^2}{1-\xi} = f$ using the quadratic formula:

$$\xi = \frac{\sqrt{f^2 + 4f} - f}{2}$$

This gives us $\xi = 10^{-27}$: none of the particles in a candle flame are ionized (remember, we guessed there were only 10^20 particles). This makes perfect sense, because 1000C is only around 0.1eV, a good two orders of magnitude less than the ionization potential. The particle density is too low to make up for that.

If you think any of my approximations don't apply (personally, I'm not too sure about the particle density) then please correct me in a comment!

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Your error lies in the fact you assume the ionization to start from the fundamental n=1 state. In a flamme, electrons first climb by collision the energy ladder up to some excited states. When their bounding energy is close to the thermal energy they get ionized. – Shaktyai Sep 4 '12 at 13:23
I see what you mean, but I don't think you're quite right. The vast majority of atoms in a plasma are either ionized or in the ground state. This is because the continuum has a huge statistical weight compared to the bound states (the density of states is large). You can actually use (a slightly more general form of) the Saha equation to find out how many atoms are in the excited states in a Hydrogen plasma; it turns out it's safe to ignore all except the ground state. – poorsod Sep 4 '12 at 14:31
I did run a kinetic (Fokker Planck) atomic code for fusion plasmas at the edge of Tokamaks. At 0.1 eV all the gas is ionized. The energy difference between the n=6 and n=7 is already of the order of 0.1 eV. And collisions pump up level by level electrons from ground state to the continuum. The problem is extremely complex because the system is not in thermodynamical equilibrium (because of radiations)and one needs to introduce different temperatures for the upper levels, the lower ones and the free electrons. – Shaktyai Sep 4 '12 at 16:07
Flames can have non-negligible ionization due to chemical reactions involving free radicals (starting, in hydrocarbon flames, with ${\rm CH+O\rightarrow CHO^{+}}+e^{-}$). Check this old survey about the topic for more information. – mmc Sep 5 '12 at 2:40

Nope. Fire is a thermal phenomenon, plasma is more of electrical.

## What's plasma?

Plasma is the state when you strip off electrons/add electrons to a gas--so plasma consists of charged gas ions. It usually glows due to electron transitions and whatnot.

## What's fire?

In a flame, you basically have hot soot/&c molecules flying up. Any hot material emits photons, which are usually in the infrared range for normal temperatures. At higher temperatures, they can go into the visible range.

One way to explain this is by blackbody radiation-- the soot must emit photons since it has a nonzero temperature.

What's actually going on is that the electrons are "thermally excited"--they have extra energy and are prone to making transitions. Transitions lead to absorption/emission of light, and this is what causes the color.

You can see that there aren't any ions involved in fire, so it's not plasma. But ionization will occur if you heat it to even higher temperatures, and it can become plasma.

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Would an oxy-acetylene (welding) torch be a plasma – Martin Beckett Apr 10 '12 at 1:59
"Fire is a thermal phenomenon, plasma is more of electrical." I can't say I like this formulation much...heat alone is enough to ionize atoms if things get hot enough. – dmckee Apr 10 '12 at 2:23
@dmckee: But ionization will occur if you heat it to even higher temperatures, and it can become a plasma. I know, but it's not hot enough in fire.. – Manishearth Apr 10 '12 at 3:19
@MartinBeckett in some instruments yes : directindustry.com/prod/farley-laserlab/… – anna v Apr 10 '12 at 4:43
@annav, yes a plasma cutter is a plasma! Oxy-acetylene is about 3500C which is the bottom end of a K type star surface – Martin Beckett Apr 10 '12 at 14:46