# Angular velocity when a rod inclined to a wall slips and its subsequent motion observed from the axis of rotation

When a rod inclined to a wall slips, rate of change of which angle does the angular velocity represent? Is it the rate of change of angle with which the rod is inclined to the horizontal ? I'm not able to visualize it. In pure rotation it is quite simple to see which angle is changing and hence the angular velocity. Also, is centre of mass of the rod the axis of rotation? If so how would the motion of rod look when observing from the axis. It doesn't appear seem to be like a circle, though I'm only saying it through my intuition. A diagram perhaps would help in my visualisation.(Assume no friction anywhere)

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Let $\alpha$ be the angle between the rod and the floor at point $B$ (see my drawing). Then we can write the points $A$ and $B$ with the length $L$ of the rod as $$\vec A = L \sin(\alpha) \begin{pmatrix} 0 \\ 1 \end{pmatrix} \,,\qquad \vec B = L \cos(\alpha) \begin{pmatrix} 1 \\ 0 \end{pmatrix} \,.$$
The center of gravity $M$ of the rod is just the average of $A$ and $B$. It is $$\vec M = \frac{\vec A + \vec B}2 = \frac L2 \begin{pmatrix} \cos(\alpha) \\ \sin(\alpha) \end{pmatrix} \,.$$
The angular velocity should just be $$\omega = \frac{\mathrm d}{\mathrm dt} \alpha \,$$ nothing more. The motion of the rod is translation as well as rotation. The rotation around any point can always be separated into a center-of-mass motion and a center-of-mass rotation.
In the center of mass frame you would only see the rotation. This frame is attached to the red dot. You would just see the rod being rotated by $\alpha$. Or are you interested in the exact time evolution of this motion? – Martin Ueding Feb 2 at 17:52