Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

I'm trying to wrap my head around how geodesics describe trajectories at the moment.

I get that for events to be causally connected, they must be connected by a timelike curve, so free objects must move along a timelike geodesic. And a timelike geodesic can be defined as a geodesic that lies within the light cone.

I want to know why exactly null geodesics define the light cone. Or, why null geodesics define the path of light.

Also, if there's a better explanation why matter follows timelike geodesics, that would also be welcome.

share|improve this question
add comment

1 Answer

up vote 5 down vote accepted

Even in curved spacetime, you can perform a coordinate transformation at any location ("move to a freely falling frame") such that your metric is locally flat , and takes the form \begin{equation} ds^2 = -c^2 dt^2 + dx^2 + dy^2 + dz^2\end{equation}

If you consider a null trajectory where $ds^2$ is set to 0, then the above equation is the statement that "the differential physical distance traveled along the trajectory, as measured by an observer in a freely falling frame at the location in consideration, is equal to the speed of light times the differential time interval measured by that observer." From Einstein's equivalence principle, this is precisely the way that light must behave.

share|improve this answer
    
+1 for coord transformation. –  P O'Conbhui Mar 31 '12 at 1:21
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.