I'm trying to understand the derivation of the angular momentum commutator relations. How is
$$[zp_y, zp_x] ~=~ 0?$$
How is
$$[yp_z, zp_x] ~=~ y[p_z, z]p_x?$$
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I'm trying to understand the derivation of the angular momentum commutator relations. How is $$[zp_y, zp_x] ~=~ 0?$$ How is $$[yp_z, zp_x] ~=~ y[p_z, z]p_x?$$ |
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Remember that $$[AB,C] = A[B,C] + [A,C]B$$ With this, the first identity follows directly from the canonical commutation relation $$[x_i,p_j] = i \hbar \delta_{ij}$$ along with $$[x_i,x_j] = [p_i,p_j] = 0$$ For the second, the same relations tell us that $y$ and $p_x$ commute with everything else in sight, and so can be treated as C-numbers. |
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