Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I'd like to understand better how emulsifiers prevent droplet coalescence. There must be something more they do than just lower the surface tension between the droplet and the ambient substance. I tried to look up the answer but there's a lot of qualitative semi-explanations floating around that seem to choke out any precise explanation. If anyone can give a detailed explanation, that would be great!

share|cite|improve this question
Well for anything that goes beyond the qualitative you'd need specific examples, like oil in water. In that case the emulsifier would have a hydrophile and a lipophile end and thus overcome the repulsion between oil and water – Lagerbaer Feb 25 '12 at 4:37
Yes, I specifically had oil and water in mind, but I'd like to learn anything about them I guess. Are vastly different mechanisms responsible in other cases? – josh Feb 25 '12 at 7:02
up vote 2 down vote accepted

In general emulsifiers do not work by lowering the surface tension. They do lower the surface tension, but it is still thermodynamically favourable for droplets to coalesce.

Given the above I'm sure you've already guessed that the emulsifier creates a kinetic barrier. If you take an oil in water emulsion stabilised with a typical anionic surfactant, to make two drops coalesce you have to displace surfactant from the oil/water interface into either the water or the oil. There is an energy barrier associated with this process, and this prevents coalescence.

You can still break emulsions given enogh shear. For example oil in water emulsions are used in some hydraulic systems. The extreme shear involved, in e.g. pumps, overcomes the kinetic barrier and breaks the emulsion, and this is used to provide oil for lubrication where the shear is highest.

share|cite|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.