Initially, there is a single capacitor $A$ attached to a power source that charges it to a certain voltage $V$. Once it is charged, it is instantaneously removed and placed in a circuit with an uncharged capacitor. How do the charges and voltages redistribute over these two capacitors?
It seems that these capacitors would end up being in series and thus would have the same charge equal to the capacitance of $A$ multiplied by the voltage of the battery. Beyond that, I would assume that voltage can be calculated by $V=q/C$ for each capacitor?
Is this the correct approach?