I personally haven't seen the 'heat diffusion equation', though I think it is derivable from the conductivity equation.
Your intuition is misleading you. Whenever there is a temperature gradient, there is a flow of heat, governed by $$\dot{Q}=-kA\frac{\Delta T}{\Delta x}$$ This equation is a special case of Fourier's law. A flow of heat is not possible here, due to the insulator. There will be a little amount of heat flow initially to bring the system to thermal equilibrium, but no more.
The reason you're confused here is that you expect it to have a gradient, based on everyday experiences (which do not involve perfect insulators). The issue here is that we can't see a heat flow, so it is not immediately obvious that a temperature gradient causes a heat flow (and vice versa). Over here, you have a hot liquid on one side, but it is not necessary that a hot liquid gives out heat continuously. It will give out heat till the wall attains the same temperature, after which there will be no net flow of heat.
Over here I am assuming that the top and bottom of the wall are insulated (based on the 'no sources/sinks of heat'. If not, then there will be a temperature gradient, as heat flow will be enabled.
Another way of lookng at these types of questions is by paradigming electricity. Look at temperature differences as potential differences, and heat flow as current ($k$ becomes the electrical conductivity then). Imagine a battery. Connect one end to an insulator, and the other end to a resistor (this is the wall). The insulator and resistor should be now connected. Obviously, you don't get a potential difference across the resistor, as there is no current. Same concept here.