This is complete nonsense. The probability amplitude is not oscillating at all in the classical limit, rather it is a bump at a certain position with a certain momentum.
The example picture you give is of a moderately large n energy eigenstate. In this energy eigenstate, the particle is bouncing back and forth smeared out over the whole line, so that it continuously interferes with itself going in opposite directions, giving rise to a real valued wavefunction with maxima and minima.
For a real particle whose position is seen by continuous measurement by photons, like a classical mass on a spring, the energy is indefinite. The known position and momentum make a smeared out wavepacket when you measure all the outgoing photons (otherwise it's a density matrix). The wavefunction appropriate to such a thing is a localized wave-packet of width comparable to the wavelength of light, which has a complex amplitude that varies as the momentum. A model for such a state is
$$ \psi(x) = e^{-a x^2 + ip\cdot x}$$
You can write such a state as a superposition of nearby energy eigenstates, and it doesn't have any minima. The minima appear only when a wave diffracts off a reflecting barrier and interferes with itself going the other way, something which is only relevant near the classical turning points.
If you actually had a particle carefully prepared in the state you pictured, a detector which looked to see if the particle was at a minimum would never find the particle. If it looked near the maxima, it would find the particle at a higher rate than the classical density. The average density of the particle is still given by
$$ \langle|\psi(x)|^2 \rangle = {T\over v(x)}$$
Where T is the classical period and v is the classical velocity at position x. But the interpretation that this is a classical motion is not correct, and is being misused by the author of the book.