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The electromagnetic force on a charge $e$ is

$$F=e(E+v\times B),$$

the Lorentz force. But, is this a separate assumption added to the full Maxwell's equations? (the result of some empirical evidence?) Or is it somewhere hidden in Maxwell's equations?

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See David Zaslavsky's answer to this question physics.stackexchange.com/q/15443/2451 – Qmechanic Feb 3 '12 at 14:11

3 Answers

up vote 5 down vote accepted

Maxwell's equations do not contain any information about the effect of fields on charges. One can imagine an alternate universe where electric and magnetic fields create no forces on any charges, yet Maxwell's equations still hold. (E and B would be unobservable and totally pointless to calculate in this universe, but you could still calculate them!) So you can't derive the Lorentz force law from Maxwell's equations alone. It is a separate law.

However...

--> Some people count a broad version of "Faraday's law" as part of "Maxwell's equations". The broad version of Faraday's law is "EMF = derivative of flux" (as opposed to the narrow version "curl E = derivative of B"). EMF is defined as the energy gain of charges traveling through a circuit, so this law gives information about forces on charges, and I think you can derive the Lorentz force starting from here. (By comparison, "curl E = dB/dt" talks about electric and magnetic fields, but doesn't explicitly say how or whether those fields affect charges.)

--> Some people take the Lorentz force law to be essentially the definition of electric and magnetic fields, in which case it's part of the foundation on which Maxwell's equations are built.

--> If you assume the electric force part of the Lorentz force law (F=qE), AND you assume special relativity, you can derive the magnetic force part (F=qv x B) from Maxwell's equations, because an electric force in one frame is magnetic in other frames. The reverse is also true: If you assume the magnetic force formula and you assume special relativity, then you can derive the electric force formula.

--> If you assume the formulas for the energy and/or momentum of electromagnetic fields, then conservation of energy and/or momentum implies that the fields have to generate forces on charges, and presumably you can derive the exact Lorentz force law.

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So Faraday was playing a fool and Maxwell speculated without any idea how electric and magnetic fields affect charges? No, Faraday and Maxwell dealt with macroscopic charges (densities) and currents (current densities), not with a point-like charge as H. Lorentz did, that's the difference. – Vladimir Kalitvianski Feb 3 '12 at 17:29
The expression of the Lorentz force in terms of electromagnetic fields can be derived from 4-divergence of EM field stress-energy tensor. But it is only half of the work. You can then derive the Lorentz force in terms of flux/charge densities if you assume that the action of magnetic field on flux 4-vector is rotation around direction of magnetic field, to the angle proportional to the magnitude of field. Similarly, the action of electric field on flux is Lorentz boost in the direction of electric field, proportional to the magnitude of the electric field. – Murod Abdukhakimov Feb 5 '12 at 13:14
@Vladimir Kalitvianski, as you suspect, I am assuming the questioner is asking about "Maxwell's equations in modern form", i.e. the four equations as reformulated by Heaviside, in the form that appears in textbooks these days under the label "Maxwell's equations". I am not talking about what Maxwell and Faraday originally thought or wrote. If I'm remembering correctly, you're exactly right: Maxwell and Faraday did not have much or any logical separation between fields, forces, and charges. – Steve B Feb 5 '12 at 22:20
@SteveB: I agree, if the Maxwell equations are understood as equations for the EMF sourced with a known four-current, then they do not describe the Lorentz force which is a part of "mechanical" equations. – Vladimir Kalitvianski Feb 6 '12 at 10:38

Steve B gives a very, very good answer, but I have one thing to add to his third point. He says if you assume the electric part of the force, you can derive the magnetic part from relativity. I have a different derivation for the magnetic part that doesn't exactly use relativity in an obvious way. I take a freely propagating e-m wave travelling between two metal plates. From Maxwell's equations we can get the induced charges in the plates, and also the induced currents. If we know the electrostatic force due to the charges, then the two plates must be attracted to each other. It turns out that the magnetic force is exactly equal and opposite to the electric force, so there is no net force between the plates. It's a nice calculation, and I'd like to say it allows me to derive the magnetic force, but I was never able to think of a physical reason why I would be entitled to assume that the total force between the plates must be zero.

I talk about this problem on my physics blog .

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Can you check the link to your blog? – Greg P Feb 3 '12 at 17:31
Thanks, Greg. I had an extra backslash at the end. It's OK now. – Marty Green Feb 3 '12 at 18:05

I haven't seen this mentioned in the answers so I thought I should at least mention it. If you take the perspective that Maxwell's equations are the equations describing a $U(1)$ gauge field, then minimal coupling (which is, in a sense, the only gauge invariant way of coupling matter to a gauge field) ensures than any charged particle obeys the Lorentz force law, with the only freedom being the value $e$ of its charge. So while Maxwell's equations themselves, without some additional assumptions, may not necessarily imply the Lorentz force law, $U(1)$ gauge invariance does imply the Lorentz force law. In fact, if you take $U(1)$ gauge invariance as being the fundamental starting point, then it implies both Maxwell's equations and the Lorentz force law. Again, this is a matter of perspective, so I am not disagreeing with the other answers, but I think that this is the modern point of view.

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With a better success one can proceed from the Lorentz force directly, why invoke U(1)? U(1) cannot be a fundamental starting point because it implies already the mechanical and the wave equations in place with their strict physical meaning. Gauge invariance is like invariance with respect to the potential energy constant shift $V_0$; the mechanical equations with forces do not include the absolute value of the potential energy at all, there is nothing to speak about. $V_0$-invariance cannot be a fundamental starting point to derive physics because it follows from physics, not vice versa. – Vladimir Kalitvianski Feb 5 '12 at 12:45
Minimal coupling is not the only way of coupling matter to electromagnetic field. Consider, for instance, Pauli coupling. – Murod Abdukhakimov Feb 5 '12 at 13:08
Minimal coupling does not work alone, it needs renormalizations, i.e., additional counter-terms to produce physical results. – Vladimir Kalitvianski Feb 5 '12 at 16:17

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