Suppose we have 2 fixed end connected with a wire and now we insert a vibrator in the middle of the wire, and resonance occur. How would the fundamental frequency looks like?
I know the case when the vibrator is at one ends and another ends are fixed while in this case, there are 2 fixed point and the vibrator is at the middle.
Is the fundamental frequency like this? I imagine half of the original wire acts like a wire with a vibrator at one end and get the result.
Would the fundamental frequency be different if the vibrator which is on the string is vibrating with a very large amplitude?