Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

Pair correlation function for the usual Laughlin droplet is defined as $g(\vec{r})$: $$\rho_0 g(\vec{r})=\frac{1}{N}\langle\sum_i^N \sum_{j \neq i}^N \delta(\vec{r}-\vec{r_i}+\vec{r_j})\rangle$$, where $\rho_0=\frac{\nu}{2\pi l_0^2}$. So if now the Laughlin droplet is inhomogeneous, meaning that the density function $\rho(\vec{r})$ is direction dependent, then should the pair correlation function still be defined the same as above, or do we need to change $\rho_0$ to something else?

share|improve this question

1 Answer 1

If the system is anisotropic, you'll need to consider expanding the pair correlation function to accommodate the anisotropy - typically this is done using an expansion in spherical harmonics.

share|improve this answer
    
Any paper on that I can read about? –  huyichen Feb 2 '12 at 18:08
1  
I'll look for some others, but for the case applied to metallic glasses try: prl.aps.org/abstract/PRL/v105/i20/e205502, or prb.aps.org/abstract/PRB/v35/i5/p2162_1 Also, "Underneath the Bragg Peaks" by Egami has a section on the anisotropic pair distribution function. –  Jen Feb 2 '12 at 20:20

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.