Are black hole event horizons filled with black holes? [closed]

An observer hovering close to an event horizon will observe huge energies, like blue shifted radiation falling in, or Hawking radiation going out. So does the observer observe that black holes are created, when high energy particles collide, and these black holes then absorb energy at fast rate?

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closed as not a real question by Sklivvz♦, Manishearth♦Dec 23 '12 at 8:50

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

Currently, your question isn't that clear... If you clarify it, ping me in the comments and I'd be happy to reopen it :) – Manishearth Dec 23 '12 at 8:50

Now, any other known radiation is too weak to produce black holes near the horizon for practical astrophysical situations. This is because energy concentration required to produce a horizon is immensly immense :) . Remember $E=mc^2$ - you need a lot of matter to form a black hole and still $c^2$ is sooo huge. I am working on black hole formation in my thesis and radiation can of course produce it - but simulations suggest that energy concentration has to be unreasonably strong.
Ok, so the answer is a bit different now. The redshift is a consequence of coordinate singularity - appearence of $(1-2M/r)$ in metric expressions. Coordinate system which is singular at the horizon cannot be used to analyze observers there. You need to chage coordinates to Kruskal ones - and if you do you will find that there is no infinite blue-shift. Just 'some' shift, but not that significant. See en.wikipedia.org/wiki/Kruskal–Szekeres_coordinates for details (unusually good page for wikipedia) – Terminus Feb 1 '12 at 12:13