# Effects of parallel superconducting plates

Assuming the existence of virtual particle field ( zero point energy field) Casimir force is produced by 2 parallel conducting plates excluding some of the frequencies between the plates, if these 2 plates are superconducting does that change the amount of frequencies being excluded?

One theory I've read postulates that it is interaction of matter with the ZPF (=zero point field) that is the origin of mass and inertia, if the parallel plates are suppressing the appearance of some of these virtual particles, would that not in some manner be modifying inertia for matter passing between the plates?

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Could you clarify which theory you're referring to re. the orgin of mass. Are you thinking of the Higgs mechanism ? –  twistor59 Jan 24 '12 at 9:56
This theory is one that appeals to me the most, I guess because it feels beautiful and intuitive! –  Todd Burkett Jan 25 '12 at 8:16
In the future please link to the arXiv abstract page if possible, e.g. arxiv.org/abs/gr-qc/0504061 –  Qmechanic Feb 23 '12 at 15:53

Casimir force is an effect of interaction of two neutral but quantum mechanical plates. Neutral means they are not globally charged. Quantum mechanical means they consist of many real particles and fields bound together with laws of quantum mechanics. When people use the conditions of ideal conductivity of plates and write the filed boundary conditions like $E=0$ on the surfaces, one has to keep in mind that such a condition is a solution to the coupled equations of matter and field. You cannot exclude the plates from interaction and concentrate solely on fields. If you add another particle in between, the force will change.
"Inertia" of a matter passing between plates may banally change due to interaction. For example, when you attach your probe body $m_p$ to something else $m_{se}$, the "inertia" of your probe body changes: now you have to pull not only the probe body, but also its attachment. However, this mass change is calculated and corresponds to the total mass, so the mass of the probe body $m_p$ involved into such a calculation $m_{tot}=m_p+m_{se}$ does not change, to be exact.