# Reflected optical rotation of polarised light

Assume polarised light travels through an optically active medium (e.g. water with lots of sugar) with the specific angle $\alpha_s$ of depth $d$ at which end it is reflected (so in total it travels $2d$).

Will the light at the end where it initially entered the material be polarised with a relative angle of $\alpha_sd + (-\alpha_s)d = 0$ or with $\alpha_sd + \alpha_sd = 2\alpha_sd$?

I believe it is the first, because the rotation is reversed by the medium, but is that actually correct?

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@Georg: My understanding (apparently as well as Steve B's) is that it rotates the light in both cases in the same direction, say right. Thus, for a still standing observer, the direction appears to change. I just wasn't sure if this was accurate. – bitmask Nov 10 '11 at 14:29
You are right, and I need a coffee! – Georg Nov 10 '11 at 14:33