Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

I have this problem:

A 10 kg box is resting on a frictionless table and someone drags it by a string at a 30 degree angle to the horizontal with a force of 40 Newtons. Find the acceleration of the box. Draw a free body diagram of the system.

What is a free body diagram?

share|improve this question
    
Unbelievable. This site is not for such trivial questions which can be found in any introductory physics book, come on!! –  Revo Feb 5 '12 at 23:44
    
@Revo Depending on what you mean by "trivial," that may or may not be true... anyway, after some thought I raised a meta question about this, and I'd welcome your input. –  David Z Feb 6 '12 at 3:39

2 Answers 2

To draw a free body diagram, start with a picture of the system. Draw arrows to represent all the forces exerted on parts of the system, with the tail of the arrow attached to the object that force acts on. Label the forces. Then erase everything but the arrows.

To solve the problem, you will need to determine what force accelerates the box. This should be the horizontal component of the tension in the string. To get this component, use the formula $F_x=F cos\theta$. Then apply Newton's Second Law.

share|improve this answer
    
"with the tail of the arrow attached to the object that force acts on"... is that right? Surely it's from the object that that force comes from, the head indicates the object that that force acts on, or am I confused? en.wikipedia.org/wiki/Free_body_diagram –  AJP Mar 3 '12 at 23:53

A FBD (Free Body Diagram) is a diagram where all connections have been replaced by forces. Each body at which you want to apply $\sum F = m a$ you add up vectorially the force components acting on that body. In your case, you are interested only in the vertical component of the forces acting, so add them up and make sure they add up to zero (since the body is not moving the vertical direction at all).

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.