Tell me more ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.
up vote 1 down vote favorite

The title largely sums up my question, what does happen if you either x-ray an x-ray, or point two x-ray generators at each other?

share|improve this question
4  
since an x-ray is nothing but an electromagnetic wave (with high frequency), what do you think would happen? – Physicsworks Oct 6 '11 at 10:00
XX-Rays would probably form... – valdo Oct 6 '11 at 20:44
You can see the internals of the X-ray machine. – Calmarius Sep 3 '12 at 12:26

1 Answer

up vote 6 down vote

X-rays are electromagnetic waves, just as light rays are. The difference is in the wavelength (thus frequency and Energy

Spectrum).

So your question has the same answer as "What happens if you shine light on light" or "What happens if you point a light ray at a light ray".

Classically, you will see the same effects you see with usual light rays, interference, diffraction, etc.

On a quantum-level, you will even be able to see direct interaction (light with light, or analogously x-ray with x-ray), as described in quantum electrodynamics (QED).

share|improve this answer
as photons' are uncharged I didn't think they interacted directly? – Nic Oct 6 '11 at 10:41
3  
well not directly in the sense of first order QED diagrams. But going to higher orders you can have photon-photon scattering without any problems. – luksen Oct 6 '11 at 11:07
via pair-production loops? I'm no particle physicist! – Nic Oct 6 '11 at 11:13
2  
The first contribution to light-light scattering is the box diagram with electron/positron going around the loop. For slowly varying fields, this dynamics is captured by the Euler-Heisenberg lagrangian - the seminal low-energy effective action. – Simon Oct 6 '11 at 12:26
@Simon, why don't you add that as an answer? also if you can say something at what intensities/frequencies one is expected to see measurable effects, it would be great – lurscher Oct 6 '11 at 17:26

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.