In addition to Niel's historical answer, I'll try to give a slightly more mathematical one. It will turn out that not only light travels at the speed it does, but as Jerry hinted at in his comment to Niel's answer, any particle with rest-mass zero travels at this speed.
This speed ($\approx3\cdot 10^8m/s$) could have been denoted "speed of gluons" or "speed of neutrinos" (in the Standard Model at least where neutrinos are massless"). The reason why it is called "speed of light" is that photons are by far the easiest massless particles to detect and thus were detected first, leading to the events and advances in physics that Niel described.
To recap, the postulate that the speed of light $c=\Delta x/\Delta t$ is the same in all reference frames is mathematically expressed by means of Lorentz transformations. As you may have heard Lorentz transformations not only change the coordinates of space but also time, which is necessary in order to satisfy the postulate. Lorentz transformations leave the expression $c^2t^2-x^2-y^2-z^2 = c^2t^2-\mathbf{x}^2$ invariant for all reference frames. So if it is zero (which it is for light, as is easy to see when looking at the equation at the beginning of the paragraph) it will stay zero in all frames of reference, just as we postulated. (If it is some other value, it will be this exact value in all other frames as well).
It turns out (I won't derive this here) that for the energy and momentum a similar equation holds: $\frac{E^2}{c^2}-\mathbf{p}^2=m^2c^2$. The energy got the role of time, more or less, while the momentum $p$ took over the role of the position (this is known as canonical conjugation). So written differently $E=\sqrt{\textbf{p}^2c^2+m^2c^4}$. Even if a particle doesn't have any momentum it still has energy (the famous $E=mc^2$). Another way to write the expression for the energy is $E=\gamma mc^2$ where $\gamma=\frac{1}{\sqrt{1-v^2/c^2}}$, a number known as the Lorentz factor.
As you see to have particles with finite energy the expression $\gamma m$ must be finite. But as soon as $v$ approaches $c$ the denominator in the Lorentz factor approaches zero. Assuming the mass $m$ is finite and positive this would result in the infinite Energy Niel mentioned to get the particle to move at velocity $v=c$. One can alleviate this problem by sending $m$ to zero. The energy will be finite if $v=c$ but only if $m=0$ at the same time.
If you $v>c$, $\gamma$ becomes imaginary, so to have non-imaginary energy (which is a reasonable assumption), one would need a imaginary mass, which is what tachyons are.
The takeaway here is that all massless particles move at this speed called $c$, which was just named after the most prominent particle moving at this speed, namely light. No particle with non-imaginary mass can be faster that massless particles, and massive particles can never reach the speed of massless particles (all particles "stay on their mass-shell" as physicists like to say). Remember, as $c^2t^2-\mathbf{x}^2$ has the same value in all reference frames, so does $\frac{E^2}{c^2}-\mathbf{p}^2=m^2c^2$. No matter how you boost this particle, it will always have the same value, because $m$ is a property of the particle independent of its frame of reference.