I'm still struggling with Carroll's discussion of the Newtonian Limit. I'm hoping no one will mind if I ask several questions here as they all relate to the same section (pages 105-106) of his “Lecture notes on general relativity” and I'm trying to get this thing straight in my mind.
He states that “moving slowly” means $\frac{dx^{i}}{d\tau}\ll\frac{dt}{d\tau} $ , and therefore the geodesic equation becomes $\frac{d^{2}x^{\mu}}{d\tau^{2}}=\Gamma_{00}^{\mu}+\left(\frac{dt}{d\tau}\right)^{2}=0 $
Q1. Why does $\frac{dx^{i}}{d\tau}\ll\frac{dt}{d\tau}$ ? What's the justification in assuming that the rate of change of coordinate time wrt proper time is much larger than the rate of change of distance wrt proper time? If I can understand this I (I think I) can understand why he only considers the $\Gamma_{00}^{\mu}$ Christoffel symbols.
Because the field is static, he changes the geodesic equation $\Gamma_{00}^{\mu}=-\frac{1}{2}g^{\mu\lambda}\partial_{\lambda}g_{00}$ to $\Gamma_{00}^{\mu}=-\frac{1}{2}\eta^{\mu\lambda}\partial_{\lambda}h_{00} $
Q2. So, he's gone from $g^{\mu\lambda}$ to $\eta^{\mu\lambda}$ . Is that because he ignores the $h^{\mu\lambda}$ bit of $g^{\mu\lambda}=\eta^{\mu\lambda} -h^{\mu\lambda}$ because it's negligible?
Q3. He's also gone from $g_{00}$ to $h_{00}$ . Is that because the rate of change of $g_{00}=\eta_{00}+h_{00}$ wrt $\lambda$ (I know this is a clumsy way of stating it - sorry) equals $h_{00}$ because $\eta_{00}$ doesn't change wrt to anything?
Thank you.
