# Why is the magnetic field inside a solenoid constant?

Why is the magnetic field along the length of a solenoid constant? (preferably in relatively simple terms)

Thanks!

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Why not? I mean, it does not look like a real question. If you know what the magnetic field is, of course. – Misha Aug 27 '11 at 10:47
It's a perfectly sensible question. It's essentially a question of the form, "Is this regular pattern due to a simple, deeper principle, and if so what principle?" If you don't like questions like that, then you don't like a lot of science! – Ted Bunn Aug 27 '11 at 15:53
@Ted There is no science in the question. It is school homework. I have at least three different answers in mind with different level of detalisation and the question formulation does not allow to choose between them. Yes, I don't like poorly formulated questions. – Misha Aug 27 '11 at 17:50

First, remember that the magnetic field is only uniform for a long solenoid, and even then only if you restrict your attention to regions far away from the ends.

The fundamental reason the field doesn't depend on position along the length of the solenoid is that, when you're far from the ends, the magnetic field of a long solenoid looks almost the same as that of an infinite solenoid. The field is "mostly" caused by the current relatively near you, so it doesn't matter much if the solenoid extends forever or just for a very long way. For an infinite solenoid, the field has to be uniform as a function of position along the axis, since every point along the length is the same as every other point (if you prefer, the system is translation-invariant along the axis).

I think the more surprising thing about the magnetic field inside a solenoid is not that it's uniform along the length, but that it's uniform in the perpendicular directions -- that is, that the field doesn't depend on whether you're close to the axis or far from it (as long as you're inside it). It'd be easy to imagine the field would either drop off or get stronger as you move perpendicular to the axis, but it doesn't (again, for a long solenoid when you're not near the ends).

The deep principle here is Ampere's Law. If you draw any closed loop in space, and "add up" (integrate) the tangential ("forward-pointing") component of the magnetic field around the loop, the total equals a constant times the amount of current passing through the interior of the loop. Now choose your loop to be a rectangle like, for instance, the red rectangle in the image in this website. If you move the upper side of this rectangle up and down (keeping it inside the solenoid), the enclosed current doesn't change, which means the magnetic field strength can't change.

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Remember, if we assume that the solenoid is long compared to the radius of turns, the field is approximately uniform and inside the solenoid it is parallel to its axis, while it is zero outside. This approach applies then the Ampère's law:

$$\int B. dl = \mu_0 i$$

By integrating around the solenoid we obtain:

$$B = \mu_0 N/L i$$

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So to simplify, in a solenoid you have a long straight wire bent into coils that are nearly parallel and close together. The force of a magnetic field is maximized when the current moves perpendicularly to the field lines, but is zero when it moves parallel to it; therefore, we can assume that in a solenoid the magnetic field is essentially uniform or constant because the wires are nearly parallel.

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