Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

I want to compute the components of the Riemann curvature tensor (for a case similar to the Schwarzschild solution) in 4 + 1 dimensions, but I want to use a higher-dimensional analogue of spherical coordinates. I first want to investigate a metric for the Euclidean case, i.e. "flat" space-time with no matter or energy present. How would I write this Euclidean metric using a higher-dimensional analogue of spherical coordinates?

share|improve this question
    
This link might help: en.wikipedia.org/wiki/N-sphere#Spherical_coordinates –  G. Paily Jul 29 at 19:01
    
Thanks. I had already found that page, but I've been looking for a confirmation of it. en.wikipedia.org/wiki/… also has some information, but, again, I've been looking for a non-Wikipedia source. –  HDE 226868 Jul 29 at 19:04
    
So, this?: mathworld.wolfram.com/Hypersphere.html :-D . If you look around equation 12 he gives essentially the same coordinates as the wiki article, he just numbers them differently. Confirmation is given by equation 16. Then you just need to construct $dx^{1}$, $dx^{2}$, etc. –  G. Paily Jul 29 at 19:10
    
Thanks again. This is exactly what I need. The initial discussion is also helpful. –  HDE 226868 Jul 29 at 19:19

1 Answer 1

Aren't you basically asking to the formula of higher dimensional vectors to compute yourself being in the sphere at the center with appropriate lines to all vector points?

I think I get what your asking for I asked the same questions when I was younger

Anyways here's a hyperlink to 6th dimensional operation. The operator is used in quantum physics, but clearly they are talking about bosons and fermions. The reason I am referencing this is because this goes in the quantum level from one to six dimensions as far as the x y and the z but they use all this jargon now referencing your sphere of influence that you were talking about you could always plug in the sphere formula into the equation

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.