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If my $\psi$ function is $\sin(\pi x/L)$. What is $\psi^*$ going to be?

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Can you write our your wavefunction in full, and I can tell you more accurately. –  Flint72 yesterday
I think this is valid question for Mathematics. "What is the complex conjugate of a sine function?" –  ja72 yesterday
@ja72: The question is trivial, the sine function is purely real (as $x,L \in \mathbb{R}$), so it's complex conjugate is itself. Not worth migrating. –  JamalS yesterday
Related meta post: meta.physics.stackexchange.com/q/5713/2451 –  Qmechanic yesterday
@ja72 If you check the tags, you'll see 'quantum-mechanics.' In addition, the notation suggests $\psi$ is a wavefunction, so we can assume $x\in \mathbb{R}$. And it's still trivial if $x$ is complex, as $(\sin(x))^{\ast} = \sin(x^{\ast})$. There's nothing to it. –  JamalS yesterday
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put on hold as off-topic by Brandon Enright, Kyle Kanos, ja72, David Z yesterday

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