You can view the image bigger: http://i.stack.imgur.com/4moUP.png
I'm studying RC circuits and I can't understand the part when we use Kirchoff's rule. When working with batteries, when we're going through a branch, when we hit on the negative plate first we take it's voltage to be positive. How does that work with capacitors ? How do we know which plate will be positive? Also, the person who solved this wrote:
$Vc + I1 * 1 Ω- I10 * 10 Ω = 0$
Wouldn't it be :
$Vc - I1 * 1 Ω + I10 * 10 Ω = 0$
Because, if we are going clockwise, when we're going through the $1Ω$ resistor we're going in the opposite direction of the current and for the $10 Ω$ resistor we're going in the same direction as the current. Also what if I went counterclockwise would the $Vc$ be negative? And finally is this solved correctly?