# Mechanism of Hawking's radiation and entropy of the black hole

During Hawking's radiation, a virtual particle with negative energy and mass (from pair of particle and antiparticle) fall into black hole and its real partner having positive energy escape from vicinity of black hole. And it appears to have been emitted from black hole. Since these pair of particles were present outside the black hole, flow of negative energy particles reduces its mass. As the black hole loses its mass the area of event horizon gets smaller. And so, it must decrease the entropy of the black hole.

So, how the entropy of the black hole always increase? What I am missing here. Please explain.

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It isn't true that the entropy of the black hole must always increase. Prior to the discovery of Hawking radiation there was a second law of black hole thermodynamics:

$$\frac{dA}{dt} \ge 0$$

and because the entropy is proportional to the area this means the entropy must always increase. However since the discovery of Hawking radiation this has been superceded by the generalised second law of black hole thermodynamics, which broadly states that the entropy of the black hole plus the Hawking radiation cannot decrease.

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If we accept that black holes do not indeed destroy information and that they follow the second law of thermodynamics (this is how the entropy-is-proportional-to-area formula was derived, after all) then we can forget about their being black holes and simply think of them as some object radiating black-body radiation. From this standpoint, the entropy of the black hole does not have to always increase, rather, it is the entropy of the Universe as a whole that must do so. The thermalised Hawking radiation has a microstate not fully defined by its macroscopic blackbody temperature, so it carries off entropy to compensate for that lost by the black hole. The system microstate before a radiation event is encoded in the black hole microstate and the radiation microstate, so no information is destroyed and the state of the whole system remains fully defined by the whole system state at any other time; otherwise put, the whole system state at any one time is a one-to-one function of the state at any other time.

Now this answer should be qualified by the warning that the so called Black Hole Information Paradox is not held to be resolved as yet by theoretical physicists: so it is not yet clear whether information is destroyed by black hole processes so the full answer is that no one is altogether yet sure what true entropies of black holes are. This question is foreseen to be resolved by a full theory of quantum gravity.

But for now, a plausible explanation is the classical thermodynamic one I gave. After all, as I said, a black hole's compliance with the second law of thermodynamics is how the area formula was derived in the first place.

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If you correct plank units by using Einstein's Appendix 2 of "Relativity" relation meters = i c seconds, and carry the i through all equations, converting any seconds units to meters, you get better insight. For example, this gives E= -mc^2 instead of E=mc^2, which cosmology agrees with. So you also convert all mass units to negative energy units. You then get for the entropy of a black hole a negative sign. My previous post in a different question goes into more specific detail. So the units demand entropy of a black hole is negative. Plank's constant contains an i which very much agrees with the way it is "causes" the indeterministic probabilities in QM.

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