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On Surely You're Joking Mr Feynman, when talking about the Trinity test, the author states:

the only thing that could really hurt your eyes (bright light can never hurt your eyes) is ultraviolet light. I got behind a truck windshield, because the ultraviolet can't go through glass, so that would be safe, and so I could see the damn thing.

This is also clear in this video, where the glasses are seen as black by the UV camera. If that's the case, why are sunglasses said to prevent bright sunlight and high-energy visible light from damaging or discomforting the eyes? (from Wikipedia) Is it for marketing purposes or was Feynman wrong?

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    $\begingroup$ Could you clarify the precise question you are asking? I see a bunch of them, each requiring its own answer. (Also, I think sunglasses are tinted so that you are not blinded by the light, no matter whether that would actually hurt you or not) $\endgroup$
    – ACuriousMind
    Aug 18, 2014 at 23:47
  • $\begingroup$ You have some good questions in here. Many of them are duplicates of questions on this site though. Right now your question is too broad and needs several different answers. $\endgroup$ Aug 18, 2014 at 23:56
  • $\begingroup$ Sorry, I thought since the questions were pretty similar in subject it'd be better to ask them on the same post, avoiding a bunch of links and more questions on the comments. I also searched for it beforehand (and even mentioned an answer on my question) but couldn't find a satisfying answer. Anyway, should I delete, edit it or what? $\endgroup$
    – gabrieljcs
    Aug 19, 2014 at 0:39
  • $\begingroup$ possible duplicate of Why glass is transparent? $\endgroup$ Aug 19, 2014 at 5:15
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    $\begingroup$ "Bright light can never hurt your eyes".... Obviously you've never stared into a class IV laser before. I don't care if Einstein made the claim, that is one bright light that will definitely hurt your eyes. $\endgroup$
    – Jim
    Aug 19, 2014 at 13:14

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"Bright light can never hurt your eyes" seems false to me… enough energy focused on the retina will cause damage, regardless of the wavelength. Otherwise you would not need to wear laser goggles…

That aside, materials typically have certain ranges where they absorb light more strongly than others. There is no hard and fast rule for this, but if you google "absorption spectrum glass" you will hit tons of pictures, including the following one for borosilicate glass:

enter image description here

this shows a nice flat transmission "window" from about 300 nm to about 2200 nm, covering the near UV to the infrared. This means you would see the glass as colorless, but that doesn't mean all wavelengths get through - just the ones you can see.

As for gamma rays - their energy is SO much greater, and their wavelength SO much shorter, that the mechanisms for absorption are quite different. Typically, they no longer interact with the electrons in molecular bonds (which are responsible for most of the behavior of material in the visible spectrum); they are not even interacting with the bound electrons of an atom (or rather, the binding energy becomes unimportant when the gamma ray energy is on the order of MeV); instead, they act like particles that may bounce off other particles (mostly electrons) like billiard balls - they scatter, and impart some energy to the electrons. This causes ionization, which is why this is called "ionizing radiation".

The retina will be damaged by too high an intensity of visible light: the energy will cook the proteins, and they will not recover. Recall that retinal detachment is corrected surgically by laser - "spot welding" the retina to the back of the eyeball with a bit of cooked tissue. That bit of the retina will be blind, but if it stops the rest of the retina from flapping around it's a small price to pay. This is done with an argon laser which is in the visible part of the spectrum.

The cornea will be damaged by UV. Have you ever heard of snow blindness? The intensity of sunlight in the presence of snow (lots of reflected light) can lead to "sunburn" of the eyes. That's what Feynman protected himself against, presumably (see the above plot - glass typically absorbs in the UV).

There's much more to say about this topic - but for now I have to leave it here.

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    $\begingroup$ This seems to be transmission spectrum, rather than absorption. $\endgroup$
    – Ruslan
    Aug 19, 2014 at 7:21
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    $\begingroup$ @ruslan - yes you are right, although this image shows up when you google "absorption spectrum" it is of course a transmission spectrum... $\endgroup$
    – Floris
    Aug 19, 2014 at 10:48
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In addition to the other answers, "bright light can never hurt your eyes" has to be false -- you up the intensity of the light enough, and the energy density can get arbitrarily high.

In principle, it's possible to have light so bright that it collapses to a black hole. Before then, you'll get pair production in the light beam.

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Uv goes thru glass, I thought that comment strange when I watched it. Laminated glass (which it could have been) would shield about 95% of the uv, I believe due to the resin interlayer.

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